Euler 9 in C

#include <stdio.h>

int main(void)
{
    const int sum = 1000;

    for (int a = 1; a < sum / 3; ++a) {
        const int numerator = sum * (sum - 2 * a);
        const int denominator = 2 * (sum - a);

        if (numerator % denominator != 0)
            continue;

        const int b = numerator / denominator;
        const int c = sum - a - b;

        if (a < b && b < c) {
            printf("%d %d %d = %d\n", a, b, c, a * b * c);
            return 0;
        }
    }

    fputs("no solution\n", stderr);
    return 1;
}